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.14x^2-225x+18=0
a = .14; b = -225; c = +18;
Δ = b2-4ac
Δ = -2252-4·.14·18
Δ = 50614.92
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-225)-\sqrt{50614.92}}{2*.14}=\frac{225-\sqrt{50614.92}}{0.28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-225)+\sqrt{50614.92}}{2*.14}=\frac{225+\sqrt{50614.92}}{0.28} $
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